1,500 ft² house — the textbook example
The worked example used in NEC Annex D and in every electrician exam: 12 kW range, 5.5 kW dryer, 6 kW air conditioning.
24,600 VA → 102.5 A → 125 A service
Size a house service the way an electrician does: NEC Article 220 standard calculation, with the demand factors that stop a 40 kW house needing a 400 A service.
Square feet of habitable space. Excludes open porches, garages and unfinished basements.
Kitchen and dining receptacle circuits. Two is the code minimum, at 1,500 VA each.
1,500 VA each.
Nameplate kW. Enter 0 for a gas range. The demand figure comes from Table 220.55, not this number.
Nameplate VA. Enter 0 for a gas dryer. A 5,000 VA minimum applies.
VA. Enter 0 if gas.
Total VA of anything else fastened in place — well pump, attic fan, hot tub.
VA. Only the larger of heating and cooling is counted.
VA of the compressor and air handler.
VA of the single largest motor. 25% of it is added for starting current.
General lighting: 1,500 ft² × 3 VA = 4,500 VA. With 2 small-appliance and 1 laundry circuits, the group totals 9,000 VA before demand factors, and 5,100 VA after.
Four or more fastened-in-place appliances, so the 75% demand factor applies: 8,100 VA connected becomes 6,075 VA.
Range: 12 kW nameplate becomes 8.0 kW demand from Table 220.55. Using the nameplate figure here is the single most common error in this calculation.
127.8 A calculated → a 150 A service is the smallest standard size that carries it, leaving 15% headroom.
The worked example used in NEC Annex D and in every electrician exam: 12 kW range, 5.5 kW dryer, 6 kW air conditioning.
24,600 VA → 102.5 A → 125 A service
Electric everything — range, dryer, water heater and heat pump. This is where 200 A becomes necessary.
Heating wins over cooling; lands around 200 A
Gas range, gas dryer, gas water heater. Notice how much smaller the service becomes.
Roughly half the load of the all-electric case
A 48 A charger is 11,520 VA of continuous load. Run this before promising a customer it will fit.
The charger alone can push a 150 A service past its limit
When to use this: deciding whether a house needs a 100 A, 150 A or 200 A service; checking whether an existing panel can take an EV charger or a heat pump; or sanity-checking a figure an electrician has quoted you.
The obvious approach — add up every appliance nameplate — gives a wildly wrong answer. A modest house has perhaps 40 kW of connected equipment, which at 240 V would suggest a 170 A service before you have plugged in a single lamp. But you never run all of it at once, and the NEC codifies that reality as demand factors.
The standard calculation, in the order the code specifies:
The order matters because the demand factors apply to one specific group. Applying them to the whole total, or to the appliances, is the error that makes two people's hand calculations disagree.
Only the first 3,000 VA of the lighting group counts in full:
| Portion of the lighting group | Demand factor |
|---|---|
| First 3,000 VA | 100% |
| 3,001 to 120,000 VA | 35% |
| Above 120,000 VA | 25% |
For a 1,500 ft² house: general lighting is 4,500 VA, plus 3,000 VA of small-appliance circuits and 1,500 VA of laundry, giving 9,000 VA connected. After demand factors that becomes 3,000 + (6,000 × 0.35) = 5,100 VA — a 43% reduction, and the single biggest saving in the whole calculation.
Table 220.55 sets the demand for one household range at 8 kW for any nameplate up to 12 kW. Above that, add 5% for each additional kilowatt.
| Range nameplate | Demand used |
|---|---|
| 8 kW | 8 kW |
| 12 kW | 8 kW |
| 14 kW | 8.8 kW |
| 16 kW | 9.6 kW |
The logic is that a range never draws nameplate for any length of time. Elements thermostatically cycle, and you rarely run four burners and the oven simultaneously at full power. Using nameplate instead of the table is the most common error in this calculation and it oversizes the service — expensively, since a service upgrade is largely labour.
12 kW range, 5.5 kW dryer, 6 kW air conditioning, gas water heating.
| Step | Connected | Demand |
|---|---|---|
| General lighting (1,500 × 3) | 4,500 VA | 5,100 VA |
| Small-appliance (2 × 1,500) | 3,000 VA | |
| Laundry | 1,500 VA | |
| Range (Table 220.55) | 12,000 VA | 8,000 VA |
| Dryer | 5,500 VA | 5,500 VA |
| Air conditioning | 6,000 VA | 6,000 VA |
| Total | 32,500 VA | 24,600 VA |
24,600 / 240 = 102.5 A → the smallest standard service that carries it is 125 A.
Note the gap: 32,500 VA connected, 24,600 VA demand. Without the code's demand factors this house would appear to need a 150 A service instead of 125 A.
| Service | Typically suits |
|---|---|
| 60 A | Pre-1960 housing, small apartments. Rarely adequate today. |
| 100 A | Small to mid-size home with gas heating, cooking and hot water. |
| 150 A | Mid-size home with some electric appliances. |
| 200 A | The modern default. All-electric homes, heat pumps, EV charging. |
| 400 A | Large all-electric homes, workshops, multiple EV chargers. |
The trend is firmly upward. Electrification — heat pumps replacing gas furnaces, induction replacing gas ranges, EV charging — is pushing houses that were comfortable on 100 A towards 200 A.
This is now the most common reason to run a load calculation on an existing house. A charger is a continuous load, so it is counted at 125% of its rating:
| Charger | Rating | Counted as |
|---|---|---|
| Level 1 (120 V) | 12 A | 1,800 VA |
| Level 2, 32 A | 7,680 VA | 9,600 VA |
| Level 2, 48 A | 11,520 VA | 14,400 VA |
A 48 A charger adds 14,400 VA — 60 A at 240 V — to the calculated load. That is enough to push many 150 A services past their limit on its own.
If it does not fit, the alternatives before a full service upgrade are: set the charger to a lower current (most are configurable, and 32 A still adds roughly 40 km of range per hour), or fit an energy management system that sheds the charger when the rest of the house draws heavily. The code explicitly permits load management as an alternative to upsizing.
Article 220 also contains an optional method for dwellings, which usually produces a smaller result. It takes the first 10 kVA of general load at 100% and everything above at 40%, with separate rules for heating and cooling.
For an existing house that fails the standard calculation, running the optional method is the first thing to try — it frequently shows the service is adequate after all. This calculator implements the standard method, which is the conservative one.
Habitable square feet. This sets the general lighting load at 3 VA per square foot, which covers all the lighting and general-purpose receptacles.
Two small-appliance circuits are the code minimum, at 1,500 VA each, plus 1,500 VA for laundry. These are counted whether or not anything is plugged in.
Range, dryer, water heater and the rest. The calculator applies the code demand factors — do not pre-reduce them yourself.
Both, even though only the larger will count. They cannot run at once, so the code lets you omit the smaller.
The smallest standard size that carries the calculated load. If the headroom is under 10%, seriously consider going one size up.
Using the NEC Article 220 standard method: start with 3 VA per square foot for general lighting, add 1,500 VA per small-appliance circuit and 1,500 VA for laundry, apply the demand factors to that group, then add the fixed appliances, the range demand from Table 220.55, the dryer at nameplate or 5,000 VA, the larger of heating or cooling, and 25% of the largest motor. Divide the total VA by the service voltage to get amps.
Divide your calculated total VA by 240 and round up to the next standard size — 100, 125, 150, 200, 225 or 400 A. Most modern homes land on 150 A or 200 A. A gas-appliance house of moderate size can be fine on 100 A; an all-electric house with a heat pump usually needs 200 A.
They account for the fact that not everything runs at once. You will never simultaneously use every light, every receptacle, the oven at full power and the dryer. The code recognises this: only the first 3,000 VA of the lighting group counts at 100%, and the remainder at 35%. Without demand factors, a typical house would calculate at nearly double its real requirement.
Table 220.55 sets the demand for a single household range at 8 kW for any nameplate rating up to 12 kW. A range never draws full nameplate for long — the elements cycle, and you rarely run every element and the oven together. Using the nameplate figure instead of the table is the most common mistake in this calculation, and it oversizes the service.
Because they are noncoincident — you do not heat and cool the house at the same time. The code allows you to count only the larger of the two. In a cold climate the heating load usually wins; in a hot one, the air conditioning.
When there are four or more fastened-in-place appliances other than the range, dryer, space heating and air conditioning. Water heater, dishwasher, disposal and built-in microwave is exactly four, so most kitchens qualify. With three, they count at full nameplate.
Run this calculation with the charger included as a fixed appliance and see whether the result still fits. A 48 A charger is 11,520 VA of continuous load, which is enough to push many 150 A services over. If it does not fit, the options are a service upgrade, a lower charger setting, or a load management device that sheds the charger when the rest of the house is drawing heavily.
No. This implements the standard method as an engineering estimate and a check on someone else’s figures. Actual service sizing must be done by a licensed electrician against the code edition your authority having jurisdiction has adopted, and there is also an optional calculation method in Article 220 Part IV that often yields a smaller result for existing dwellings. Use this to understand and sanity-check, not to permit.
Last reviewed .
Diameter, cross-section, resistance and current rating for any AWG size — with separate free-air and in-conduit ampacity, because they differ by a factor of two.
ΔVVoltage drop for DC, single-phase and three-phase runs in copper or aluminium, sized in mm² or AWG, checked against IEC and NEC limits.
WPower from any two of voltage, current and resistance — then energy in kWh and what it costs to run.
FLAFull load current from motor kW or hp, including efficiency — the term most calculators drop, which understates the current by 10–15%.