10 hp, 460 V, inverse time breaker
The case that looks wrong and is not: a 35 A breaker on 12 AWG conductors.
14 A table FLC → 12 AWG, 16.5 A overload, 35 A breaker
Breaker, overload relay and conductor size for a motor circuit — three different percentages of two different currents, which is why a 40 A breaker on 12 AWG is correct rather than a violation.
Table 430.250 covers 200, 208, 230, 460 and 575 V three-phase.
430.52(B) requires the LOWEST rating that will carry the starting current.
From the motor plate. Used for the overload relay only — never for the breaker.
1.15 or more permits a 125% overload rather than 115%.
°C from the nameplate. 40 or less also permits 125%.
Table full-load current for a 10 hp 460 V motor is 14 A. 430.6(A) requires this figure for conductor and short-circuit sizing even where the nameplate says otherwise — the tables are deliberately conservative.
Conductors: 430.22 requires 125% of the table current, 17.5 A, so 12 AWG copper at 75 °C.
Overload: 430.32 sizes this on the NAMEPLATE current, not the table — 125% of 13.2 A = 16.5 A, because service factor 1.15 is 1.15 or more. This is the only place in Article 430 where the nameplate is used.
Short circuit and ground fault: Table 430.52 permits up to 250% of the table current for a inverse time breaker — 35.0 A — so a 35 A device. That calculated value is already a standard rating, so Exception 1 does not arise.
Note what this produces: a 35 A device ahead of 12 AWG conductors rated 18 A. That is correct and required. The breaker is sized to let locked-rotor inrush through without opening; the overload relay at 16.5 A is what actually protects the conductors from sustained overcurrent. Applying 240.4(D) here and fitting a small breaker gives a motor that trips every time it starts.
Same motor on other devices: dual-element (time-delay) fuse 25 A, non-time-delay fuse 45 A. 430.52(B) requires the LOWEST rating that will carry the starting current, so a time-delay fuse protects the circuit far more closely than a breaker.
If the motor will not start on 35 A, 430.52(C)(1) Exception 2 permits up to 400% — 56 A — but only after it has demonstrably failed to start. It is not a free upgrade.
Nameplate 13.2 A differs from the table's 14 A. That is normal and both are used: the table for conductors and the breaker, the nameplate for the overload relay.
The case that looks wrong and is not: a 35 A breaker on 12 AWG conductors.
14 A table FLC → 12 AWG, 16.5 A overload, 35 A breaker
175% instead of 250%. Far closer protection for the same motor.
24.5 A ceiling → 25 A fuse rather than a 35 A breaker
Larger machine, same three rules.
65 A table FLC, 81.25 A of conductor, 150 A breaker
Table 430.248. Single-phase motors draw far more than people expect.
28 A table FLC, 115% overload because the plate has no service factor
1100% rather than 800% — efficiency comes with inrush.
A much larger instantaneous device than a standard squirrel cage motor
When to use this: specifying a motor circuit, checking an existing installation, or working out why a motor trips its breaker on start.
A motor circuit is protected twice, by two devices doing two different jobs, sized from two different currents. Merging them is where nearly all confusion in Article 430 comes from.
| What | Sized from | At | Rule |
|---|---|---|---|
| Branch conductors | Table current | 125% | 430.22 |
| Overload relay | Nameplate current | 115–125% | 430.32 |
| Short-circuit device | Table current | 150–800% | 430.52 |
| Table 430.250 full-load current | 14 A |
| Conductors — 125% of 14 | 17.5 A → 12 AWG copper |
| Overload — 125% of a 13.2 A nameplate | 16.5 A |
| Breaker — 250% of 14 | 35 A |
So: a 35 A breaker ahead of 12 AWG conductors. To anyone who has met 240.4(D) — which caps 12 AWG at 20 A — that reads as a serious violation. It is exactly what the code requires.
The breaker is not protecting the conductors from overload. The overload relay at 16.5 A does that. A motor draws six to eight times its running current for a second or two on start, so a device sized to the conductor ampacity would open every time the motor started. 430.52 therefore lets the short-circuit device be large enough to ignore inrush, and 430.32 requires a separate device sitting close to the real running current.
Fit a 20 A breaker here “to protect the wire” and you get a motor that will not start. That is the failure this arrangement exists to prevent.
NEC 430.6(A)(1) requires the table value for conductors and the short-circuit device even where the nameplate disagrees. The tables are deliberately conservative, and using them means a motor swap does not invalidate the circuit design.
430.32 requires the nameplate for the overload, because that device is protecting this particular machine rather than a generic one. This is the only place in the whole article where the nameplate is used, and reversing the two is the most common mistake here.
As a percentage of full-load current. These are ceilings, not targets.
| Motor type | Non-time-delay fuse | Dual-element (time-delay) fuse | Instantaneous trip breaker | Inverse time breaker |
|---|---|---|---|---|
| Squirrel cage, other than Design B | 300% | 175% | 800% | 250% |
| Design B energy-efficient | 300% | 175% | 1100% | 250% |
| Synchronous | 300% | 175% | 800% | 250% |
| Wound rotor | 150% | 150% | 800% | 150% |
| DC, constant voltage | 150% | 150% | 250% | 150% |
430.52(B) requires the lowest rating that will carry the starting current, so these percentages are where you stop, not where you start. A dual-element time-delay fuse protects the same motor far more closely than a breaker — 175% against 250% — because it tolerates inrush by design rather than by being oversized.
| Device | Percent | Ceiling | Device fitted |
|---|---|---|---|
| Non-time-delay fuse | 300% | 42.0 A | 45 A |
| Dual-element (time-delay) fuse | 175% | 24.5 A | 25 A |
| Instantaneous trip breaker | 800% | 112.0 A | 125 A |
| Inverse time breaker | 250% | 35.0 A | 35 A |
Three-phase induction motors, amperes. This is the number every calculation starts from.
| hp | 200 V | 208 V | 230 V | 460 V | 575 V |
|---|---|---|---|---|---|
| 1 | 4.8 | 4.6 | 4.2 | 2.1 | 1.7 |
| 3 | 11 | 10.6 | 9.6 | 4.8 | 3.9 |
| 5 | 17.5 | 16.7 | 15.2 | 7.6 | 6.1 |
| 10 | 32.2 | 30.8 | 28 | 14 | 11 |
| 15 | 48.3 | 46.2 | 42 | 21 | 17 |
| 20 | 62.1 | 59.4 | 54 | 27 | 22 |
| 25 | 78.2 | 74.8 | 68 | 34 | 27 |
| 30 | 92 | 88 | 80 | 40 | 32 |
| 40 | 120 | 114 | 104 | 52 | 41 |
| 50 | 150 | 143 | 130 | 65 | 52 |
| 60 | 177 | 169 | 154 | 77 | 62 |
| 75 | 221 | 211 | 192 | 96 | 77 |
| 100 | 285 | 273 | 248 | 124 | 99 |
| 125 | 359 | 343 | 312 | 156 | 125 |
| 150 | 414 | 396 | 360 | 180 | 144 |
| 200 | 552 | 528 | 480 | 240 | 192 |
430.52(C)(1) Exception 1 permits the next standard size up where the calculated value is not a standard rating. Under 240.4 you normally round down to protect the conductor; here you round up, because the device is not protecting the conductor from overload in the first place.
A 5 hp 460 V motor at 7.6 A × 250% = 19 A, which is not a standard rating, so a 20 A breaker is permitted. A 10 hp at 14 A × 250% = 35 A, which is standard, so the exception never arises and 35 A is the answer.
430.52(C)(1) Exception 2 raises the ceilings — 400% for an inverse time breaker or non-time-delay fuse, 225% for a dual-element fuse, 1300% for an instantaneous trip breaker. The condition is that the standard value has demonstrably failed to carry the starting current. It is a remedy, not a default: jumping straight to it leaves the circuit with far weaker short-circuit protection than it should have.
430.62: the feeder device may not exceed the largest branch-circuit device in the group, plus the full-load currents of all the other motors. Not the sum of the branch devices, which would be enormous.
Three motors on one feeder — a 10 hp with a 35 A breaker, plus a 5 hp at 7.6 A and a 3 hp at 4.8 A — give 35 + 7.6 + 4.8 = 47.4 A, so a 50 A feeder device. Adding the three branch devices would have suggested 35 + 20 + 15 = 70 A. Conductors come from 430.24: 125% of the largest motor plus the full-load currents of the rest.
From Table 430.250 for three-phase or 430.248 for single-phase, by horsepower and voltage. NEC 430.6(A) requires this figure — not the nameplate — for conductor and short-circuit sizing.
430.22. A continuous-duty motor branch circuit takes conductors rated at least 125% of the table current.
430.32. This is the one place the nameplate is used: 125% of nameplate amps if the service factor is 1.15 or more or the temperature rise is 40 °C or less, otherwise 115%.
A percentage of the table current that depends on the device type — 250% for an inverse time breaker, 175% for a time-delay fuse. These are ceilings, and 430.52(B) requires the lowest rating that will actually start the motor.
430.52(C)(1) Exception 1 permits the next standard size where the calculated value is not one. Note that this is the opposite of the general rule in 240.4.
For a standard squirrel cage motor on an inverse time breaker, up to 250% of the table full-load current from NEC Table 430.250 — so a 10 hp 460 V motor at 14 A takes a 35 A breaker. For a dual-element time-delay fuse it is 175%, giving 25 A for the same motor. These are maximums; 430.52(B) requires the lowest rating that will carry the starting current.
Because it is not protecting the wire from overload — the overload relay does that. A motor draws six to eight times its running current for a second or two on start, and a breaker sized to the conductor ampacity would trip every time. So 430.52 lets the short-circuit device be large enough to ignore inrush, and 430.32 requires a separate overload device sized close to the actual running current. A 35 A breaker ahead of 12 AWG conductors with a 16.5 A overload relay is fully compliant.
Both, for different things. NEC 430.6(A)(1) requires the table value from 430.248 or 430.250 for sizing conductors and the short-circuit device, even where the nameplate disagrees — the tables are deliberately conservative. 430.32 requires the nameplate for the overload relay, because that device is protecting this particular motor rather than a generic one. Getting these the wrong way round is the most common error in motor circuits.
125% of the nameplate full-load amps if the motor has a marked service factor of 1.15 or higher, or a marked temperature rise of 40 °C or less. Otherwise 115%. If the motor will not start or carry its load, 430.32(C) permits an increase to 140% and 130% respectively — but only after it has actually failed, not as a default.
125% of the table full-load current, per 430.22. A 10 hp 460 V motor at 14 A needs conductors rated 17.5 A, which is 12 AWG copper at 75 °C. Note that the derating and terminal rules still apply on top — our wire size calculator handles those, and long runs will push the size up for voltage drop.
Because it tolerates inrush by design rather than by being oversized. A dual-element fuse has a slow element for overload and a fast one for short circuits, so it can sit at 175% of full-load current and still ride through starting. An inverse time breaker needs 250% to do the same job. The fuse therefore gives closer short-circuit protection, at the cost of replacing it when it operates.
Design B is a NEMA classification for energy-efficient motors. Their higher efficiency comes from lower rotor resistance, which means higher locked-rotor inrush, so Table 430.52 allows 1100% on an instantaneous trip breaker rather than the usual 800%. The other three device types get the same percentages as any other squirrel cage motor.
NEC 430.62: the feeder device may not exceed the largest branch-circuit short-circuit device in the group, plus the sum of the full-load currents of all the other motors. Not the sum of all the branch devices, which would be far too large. Feeder conductors are sized under 430.24 at 125% of the largest motor plus the full-load currents of the rest.
Yes — 430.52(C)(1) Exception 1 permits it, which is worth noting because it is the opposite of the general rule. Under 240.4 you normally round down to protect the conductor; for motor short-circuit protection you round up, because the device is not protecting the conductor from overload in the first place.
430.52(C)(1) Exception 2 permits higher ceilings — 400% for an inverse time breaker or non-time-delay fuse, 225% for a dual-element fuse, 1300% for an instantaneous trip breaker. The condition is that the standard value has demonstrably failed to carry the starting current. It is a remedy, not a default, and jumping straight to it leaves the circuit with much weaker short-circuit protection than it should have.

Technical reviewer
Electrician · 10+ years of installation work in Bangladesh and the wider South Asian region
He reads the result the way an installer would: are the defaults values people actually meet, does the warning fire where you would stop and think, and is the answer something you could buy and fit? The code figures themselves come from the published standards cited below, not from him — that boundary is set out on his profile.
The full process is written up in the methodology and editorial policy. Results are engineering guidance, not a code sign-off — see the disclaimer. If a result looks wrong, tell us; corrections are answered before anything else.
Full load current from motor kW or hp, including efficiency — the term most calculators drop, which understates the current by 10–15%.
EGCEquipment grounding conductor size from the breaker rating — including the 250.122(B) proportional increase almost every other calculator leaves out when a run is upsized for voltage drop.
AWGWhat size wire you need, from the load, the run length and the conditions — sized against both NEC ampacity and voltage drop, with the terminal temperature rule that stops 90 °C wire giving 90 °C ampacity.
IpfThe highest current a fault could produce, from a loop impedance, a transformer nameplate or your meter readings — checked against the breaking capacity of the device that has to interrupt it.